What are the solutions to the equation 2x^2(2x^2-9)=0 ?

The solutions to the equation 2x^2(2x^2-9)=0 are x=0,x=-3/(sqrt(2)),x= 3/(sqrt(2))

Find the zeros of 2x^2(2x^2-9)=0

The zeros of 2x^2(2x^2-9)=0 are x=0,x=-3/(sqrt(2)),x= 3/(sqrt(2))

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2 x^{2} (2 x^{2} - 9) = 0

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

Decimal Notation

x = 0, x = - 2.12132 \dots, x = 2.12132 \dots

Solution steps

2 x^{2} (2 x^{2} - 9) = 0

Factor

2 x^{2} (2 x^{2} - 9) : 2 x^{2} (2 x + 3) (2 x - 3)

2 x^{2} (2 x + 3) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 3 = 0 or 2 x - 3 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions are

x = 0, x = - \frac{3}{2}, x = \frac{3}{2}

x^{3} = 250

11 x^{3} + 17 x^{2} - 21 x + 5 = 0

x^{3} = 2 - x

x^{3} - 4 x^{2} + 16 x - 64 = 0

x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 1 = 0

What are the solutions to the equation 2x^2(2x^2-9)=0 ?
The solutions to the equation 2x^2(2x^2-9)=0 are x=0,x=-3/(sqrt(2)),x= 3/(sqrt(2))
Find the zeros of 2x^2(2x^2-9)=0
The zeros of 2x^2(2x^2-9)=0 are x=0,x=-3/(sqrt(2)),x= 3/(sqrt(2))