What are the solutions to the equation 0=4x^3-24x^2-x+6 ?

The solutions to the equation 0=4x^3-24x^2-x+6 are x=6,x=-1/2 ,x= 1/2

Find the zeros of 0=4x^3-24x^2-x+6

The zeros of 0=4x^3-24x^2-x+6 are x=6,x=-1/2 ,x= 1/2

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0 = 4 x^{3} - 24 x^{2} - x + 6

x = 6, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 6, x = - 0.5, x = 0.5

Solution steps

0 = 4 x^{3} - 24 x^{2} - x + 6

Switch sides

4 x^{3} - 24 x^{2} - x + 6 = 0

Factor

4 x^{3} - 24 x^{2} - x + 6 : (x - 6) (2 x + 1) (2 x - 1)

(x - 6) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x - 6 = 0 : x = 6

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 6, x = - \frac{1}{2}, x = \frac{1}{2}

x^{3} + 7 x + 6 = 0

z^{4} = 196

x^{4} - 4 x^{3} + 4 x^{2} = 0

y^{4} = 169

(x^{2} - 7 x + 11)^{8} = 1

What are the solutions to the equation 0=4x^3-24x^2-x+6 ?
The solutions to the equation 0=4x^3-24x^2-x+6 are x=6,x=-1/2 ,x= 1/2
Find the zeros of 0=4x^3-24x^2-x+6
The zeros of 0=4x^3-24x^2-x+6 are x=6,x=-1/2 ,x= 1/2