What are the solutions to the equation x^4-5x^3-7x^2+29x=-30 ?

The solutions to the equation x^4-5x^3-7x^2+29x=-30 are x=-1,x=-2,x=3,x=5

Find the zeros of x^4-5x^3-7x^2+29x=-30

The zeros of x^4-5x^3-7x^2+29x=-30 are x=-1,x=-2,x=3,x=5

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x^{4} - 5 x^{3} - 7 x^{2} + 29 x = - 30

x = - 1, x = - 2, x = 3, x = 5

Solution steps

x^{4} - 5 x^{3} - 7 x^{2} + 29 x = - 30

Move

30

to the left side

x^{4} - 5 x^{3} - 7 x^{2} + 29 x + 30 = 0

Factor

x^{4} - 5 x^{3} - 7 x^{2} + 29 x + 30 : (x + 1) (x + 2) (x - 3) (x - 5)

(x + 1) (x + 2) (x - 3) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 2 = 0 or x - 3 = 0 or x - 5 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 2 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

Solve

x - 5 = 0 : x = 5

The solutions are

x = - 1, x = - 2, x = 3, x = 5

n^{3} = 2 n

x^{3} + 2 x = 400

11000 = 3000 (1 + x)^{5}

3 x^{3} - 2 x^{2} + x - 1 = 0

- x^{3} - 2 x^{2} - x = 0

What are the solutions to the equation x^4-5x^3-7x^2+29x=-30 ?
The solutions to the equation x^4-5x^3-7x^2+29x=-30 are x=-1,x=-2,x=3,x=5
Find the zeros of x^4-5x^3-7x^2+29x=-30
The zeros of x^4-5x^3-7x^2+29x=-30 are x=-1,x=-2,x=3,x=5