What are the solutions to the equation x^3-i=0 ?

The solutions to the equation x^3-i=0 are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i

Find the zeros of x^3-i=0

The zeros of x^3-i=0 are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i

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x^{3} - i = 0

x = \frac{3}{2} + i \frac{1}{2}, x = - \frac{3}{2} + i \frac{1}{2}, x = - i

Solution steps

x^{3} - i = 0

Move

i

to the right side

x^{3} = i

For

z^{n} = a

the solutions are

k = 0, 1, \dots, n - 1

For

n = 3, a = i

∣ a ∣ = 1

ar g (a) = \frac{π}{2}

Simplify

x = \frac{3}{2} + i \frac{1}{2}, x = - \frac{3}{2} + i \frac{1}{2}, x = - i

6 x^{4} - 13 x^{2} + 6 = 0

x^{3} - 4 x^{2} - 2 x + 8 = 0

x^{3} - 7 x^{2} + 15 x - 9 = 0

z^{3} - z^{2} + z - 1 = 0

y^{4} + 3 y^{2} - 4 = 0

What are the solutions to the equation x^3-i=0 ?
The solutions to the equation x^3-i=0 are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i
Find the zeros of x^3-i=0
The zeros of x^3-i=0 are x=(sqrt(3))/2+i 1/2 ,x=-(sqrt(3))/2+i 1/2 ,x=-i