What are the solutions to the equation 2x^4+3x^2-20=0 ?

The solutions to the equation 2x^4+3x^2-20=0 are x=sqrt(5/2),x=-sqrt(5/2),x=2i,x=-2i

Find the zeros of 2x^4+3x^2-20=0

The zeros of 2x^4+3x^2-20=0 are x=sqrt(5/2),x=-sqrt(5/2),x=2i,x=-2i

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2 x^{4} + 3 x^{2} - 20 = 0

x = \frac{5}{2}, x = - \frac{5}{2}, x = 2 i, x = - 2 i

Solution steps

2 x^{4} + 3 x^{2} - 20 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

2 u^{2} + 3 u - 20 = 0

Solve

2 u^{2} + 3 u - 20 = 0 : u = \frac{5}{2}, u = - 4

u = \frac{5}{2}, u = - 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{5}{2} : x = \frac{5}{2}, x = - \frac{5}{2}

Solve

x^{2} = - 4 : x = 2 i, x = - 2 i

The solutions are

x = \frac{5}{2}, x = - \frac{5}{2}, x = 2 i, x = - 2 i

x^{4} - 2 x^{2} - 15 = 0

λ^{3} + 2 λ^{2} - λ - 2 = 0

x^{5} + x^{3} + 1 = 0

x (x - 1)^{2} = 0

(x - 2) (x + 1) (x - 5) = 0

What are the solutions to the equation 2x^4+3x^2-20=0 ?
The solutions to the equation 2x^4+3x^2-20=0 are x=sqrt(5/2),x=-sqrt(5/2),x=2i,x=-2i
Find the zeros of 2x^4+3x^2-20=0
The zeros of 2x^4+3x^2-20=0 are x=sqrt(5/2),x=-sqrt(5/2),x=2i,x=-2i