What are the solutions to the equation x^3-4x^2-10x+40=0 ?

The solutions to the equation x^3-4x^2-10x+40=0 are x=4,x=-sqrt(10),x=sqrt(10)

Find the zeros of x^3-4x^2-10x+40=0

The zeros of x^3-4x^2-10x+40=0 are x=4,x=-sqrt(10),x=sqrt(10)

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x^{3} - 4 x^{2} - 10 x + 40 = 0

x = 4, x = - 10, x = 10

Decimal Notation

x = 4, x = - 3.16227 \dots, x = 3.16227 \dots

Solution steps

x^{3} - 4 x^{2} - 10 x + 40 = 0

Factor

x^{3} - 4 x^{2} - 10 x + 40 : (x - 4) (x + 10) (x - 10)

(x - 4) (x + 10) (x - 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 4 = 0 or x + 10 = 0 or x - 10 = 0

Solve

x - 4 = 0 : x = 4

Solve

x + 10 = 0 : x = - 10

Solve

x - 10 = 0 : x = 10

The solutions are

x = 4, x = - 10, x = 10

x^{3} + 5 x^{2} + 4 x + 4 = 0

r^{3} - 4 r = 0

3 x^{3} + 6 x^{2} + 3 x = 0

x^{4} - 3 x^{3} + 8 x - 2 = 0

t = - t^{3} + 10 t^{2} - 29 t + 29

What are the solutions to the equation x^3-4x^2-10x+40=0 ?
The solutions to the equation x^3-4x^2-10x+40=0 are x=4,x=-sqrt(10),x=sqrt(10)
Find the zeros of x^3-4x^2-10x+40=0
The zeros of x^3-4x^2-10x+40=0 are x=4,x=-sqrt(10),x=sqrt(10)