What are the solutions to the equation 4x^3-8x^2-x+2=0 ?

The solutions to the equation 4x^3-8x^2-x+2=0 are x=2,x=-1/2 ,x= 1/2

Find the zeros of 4x^3-8x^2-x+2=0

The zeros of 4x^3-8x^2-x+2=0 are x=2,x=-1/2 ,x= 1/2

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4 x^{3} - 8 x^{2} - x + 2 = 0

x = 2, x = - \frac{1}{2}, x = \frac{1}{2}

Solution steps

4 x^{3} - 8 x^{2} - x + 2 = 0

Factor

4 x^{3} - 8 x^{2} - x + 2 : (x - 2) (2 x + 1) (2 x - 1)

(x - 2) (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 2, x = - \frac{1}{2}, x = \frac{1}{2}

9 x^{4} - 47 x^{2} + 10 = 0

x^{3} + 4 x^{2} + 3 x + 2 = 0

4 x^{3} - 6 x + 1 = 0

125 x^{3} = 64

x^{4} - 2 x^{2} + 2 = 0

What are the solutions to the equation 4x^3-8x^2-x+2=0 ?
The solutions to the equation 4x^3-8x^2-x+2=0 are x=2,x=-1/2 ,x= 1/2
Find the zeros of 4x^3-8x^2-x+2=0
The zeros of 4x^3-8x^2-x+2=0 are x=2,x=-1/2 ,x= 1/2