What are the solutions to the equation -x(6x+7)(x^2-36)=0 ?

The solutions to the equation -x(6x+7)(x^2-36)=0 are x=0,x=-6,x=6,x=-7/6

Find the zeros of -x(6x+7)(x^2-36)=0

The zeros of -x(6x+7)(x^2-36)=0 are x=0,x=-6,x=6,x=-7/6

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- x (6 x + 7) (x^{2} - 36) = 0

x = 0, x = - 6, x = 6, x = - \frac{7}{6}

Decimal Notation

x = 0, x = - 6, x = 6, x = - 1.16666 \dots

Solution steps

- x (6 x + 7) (x^{2} - 36) = 0

Factor

- x (6 x + 7) (x^{2} - 36) : - x (x + 6) (x - 6) (6 x + 7)

- x (x + 6) (x - 6) (6 x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0 or x - 6 = 0 or 6 x + 7 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

Solve

6 x + 7 = 0 : x = - \frac{7}{6}

The solutions are

x = 0, x = - 6, x = 6, x = - \frac{7}{6}

x^{5} + 125 x^{2} = 0

0 = 4 x^{4} - 17 x^{2} + 4

6 x^{3} = 11 x^{2} + 10 x

x^{4} - 6 x^{3} + 9 x^{2} = 0

x^{4} + 2 x^{2} = 0

What are the solutions to the equation -x(6x+7)(x^2-36)=0 ?
The solutions to the equation -x(6x+7)(x^2-36)=0 are x=0,x=-6,x=6,x=-7/6
Find the zeros of -x(6x+7)(x^2-36)=0
The zeros of -x(6x+7)(x^2-36)=0 are x=0,x=-6,x=6,x=-7/6