What are the solutions to the equation (X-2)(X+4)(X-5)=0 ?

The solutions to the equation (X-2)(X+4)(X-5)=0 are X=2,X=-4,X=5

Find the zeros of (X-2)(X+4)(X-5)=0

The zeros of (X-2)(X+4)(X-5)=0 are X=2,X=-4,X=5

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(X - 2) (X + 4) (X - 5) = 0

X = 2, X = - 4, X = 5

Solution steps

(X - 2) (X + 4) (X - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

X - 2 = 0 or X + 4 = 0 or X - 5 = 0

Solve

X - 2 = 0 : X = 2

Solve

X + 4 = 0 : X = - 4

Solve

X - 5 = 0 : X = 5

The solutions are

X = 2, X = - 4, X = 5

5 x^{4} = 80 x^{2}

- 3 x^{3} + 75 x = 0

x^{3} = \frac{1}{64}

9 x^{4} - 8 x^{2} - 1 = 0

x^{2} (x - 9) = 0

What are the solutions to the equation (X-2)(X+4)(X-5)=0 ?
The solutions to the equation (X-2)(X+4)(X-5)=0 are X=2,X=-4,X=5
Find the zeros of (X-2)(X+4)(X-5)=0
The zeros of (X-2)(X+4)(X-5)=0 are X=2,X=-4,X=5