What is factor 2x^6+14x^4+4x^3 ?

The solution to factor 2x^6+14x^4+4x^3 is 2x^3(x^3+7x+2)

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factor 2x^6+14x^4+4x^3

factor

2 x^{6} + 14 x^{4} + 4 x^{3}

2 x^{3} (x^{3} + 7 x + 2)

Solution steps

2 x^{6} + 14 x^{4} + 4 x^{3}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{4} = x x^{3}

= 2 x^{3} x^{3} + 14 x x^{3} + 4 x^{3}

Rewrite

14

2 \cdot 7

Rewrite

4

2 \cdot 2

= 2 x^{3} x^{3} + 2 \cdot 7 x x^{3} + 2 \cdot 2 x^{3}

Factor out common term

2 x^{3}

= 2 x^{3} (x^{3} + 7 x + 2)

\frac{2 π}{1.8}

1^{2} + 2^{2} + 3^{2}

8 - \frac{3 x + 2}{5} \geq 2 (\frac{2 x - 1}{3})

3 x - 3 \leq 3 (x - 1)

(\frac{27}{125})^{\frac{2}{3}}

What is factor 2x^6+14x^4+4x^3 ?
The solution to factor 2x^6+14x^4+4x^3 is 2x^3(x^3+7x+2)