What are the solutions to the equation t^3-5t^2+14t=0 ?

The solutions to the equation t^3-5t^2+14t=0 are t=0,t= 5/2+i(sqrt(31))/2 ,t= 5/2-i(sqrt(31))/2

Find the zeros of t^3-5t^2+14t=0

The zeros of t^3-5t^2+14t=0 are t=0,t= 5/2+i(sqrt(31))/2 ,t= 5/2-i(sqrt(31))/2

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t^{3} - 5 t^{2} + 14 t = 0

t = 0, t = \frac{5}{2} + i \frac{31}{2}, t = \frac{5}{2} - i \frac{31}{2}

Solution steps

t^{3} - 5 t^{2} + 14 t = 0

Factor

t^{3} - 5 t^{2} + 14 t : t (t^{2} - 5 t + 14)

t (t^{2} - 5 t + 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

t = 0 or t^{2} - 5 t + 14 = 0

Solve

t^{2} - 5 t + 14 = 0 : t = \frac{5}{2} + i \frac{31}{2}, t = \frac{5}{2} - i \frac{31}{2}

The solutions are

t = 0, t = \frac{5}{2} + i \frac{31}{2}, t = \frac{5}{2} - i \frac{31}{2}

x^{3} - 7 x^{2} - 25 x + 175 = 0

(3 x^{8}) \cdot x^{4} = 3 x

y^{4} = 9

x^{7} = 128

- 60 x^{3} + 30 x = 0

What are the solutions to the equation t^3-5t^2+14t=0 ?
The solutions to the equation t^3-5t^2+14t=0 are t=0,t= 5/2+i(sqrt(31))/2 ,t= 5/2-i(sqrt(31))/2
Find the zeros of t^3-5t^2+14t=0
The zeros of t^3-5t^2+14t=0 are t=0,t= 5/2+i(sqrt(31))/2 ,t= 5/2-i(sqrt(31))/2