What are the solutions to the equation -x^4-8x^3+7x^2+56x=0 ?

The solutions to the equation -x^4-8x^3+7x^2+56x=0 are x=0,x=-8,x=-sqrt(7),x=sqrt(7)

Find the zeros of -x^4-8x^3+7x^2+56x=0

The zeros of -x^4-8x^3+7x^2+56x=0 are x=0,x=-8,x=-sqrt(7),x=sqrt(7)

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- x^{4} - 8 x^{3} + 7 x^{2} + 56 x = 0

x = 0, x = - 8, x = - 7, x = 7

Decimal Notation

x = 0, x = - 8, x = - 2.64575 \dots, x = 2.64575 \dots

Solution steps

- x^{4} - 8 x^{3} + 7 x^{2} + 56 x = 0

Factor

- x^{4} - 8 x^{3} + 7 x^{2} + 56 x : - x (x + 8) (x + 7) (x - 7)

- x (x + 8) (x + 7) (x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 8 = 0 or x + 7 = 0 or x - 7 = 0

Solve

x + 8 = 0 : x = - 8

Solve

x + 7 = 0 : x = - 7

Solve

x - 7 = 0 : x = 7

The solutions are

x = 0, x = - 8, x = - 7, x = 7

x^{4} - 32 x^{2} + 256 = 0

30 x - 4 x^{2} - 2 x^{3} = 0

- λ^{3} + 5 λ^{2} - 3 λ - 9 = 0

25 x^{4} + 80 x^{2} + 64 = 0

200 x^{3} + 2000 x - 1000 = 0

What are the solutions to the equation -x^4-8x^3+7x^2+56x=0 ?
The solutions to the equation -x^4-8x^3+7x^2+56x=0 are x=0,x=-8,x=-sqrt(7),x=sqrt(7)
Find the zeros of -x^4-8x^3+7x^2+56x=0
The zeros of -x^4-8x^3+7x^2+56x=0 are x=0,x=-8,x=-sqrt(7),x=sqrt(7)