What are the solutions to the equation p^3-4p=0 ?

The solutions to the equation p^3-4p=0 are p=0,p=-2,p=2

Find the zeros of p^3-4p=0

The zeros of p^3-4p=0 are p=0,p=-2,p=2

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p^{3} - 4 p = 0

p = 0, p = - 2, p = 2

Solution steps

p^{3} - 4 p = 0

Factor

p^{3} - 4 p : p (p + 2) (p - 2)

p (p + 2) (p - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

p = 0 or p + 2 = 0 or p - 2 = 0

Solve

p + 2 = 0 : p = - 2

Solve

p - 2 = 0 : p = 2

The solutions are

p = 0, p = - 2, p = 2

605 = 5 x^{3}

b^{3} - b = 0

12 x^{4} + 7 x^{3} - 42 x^{2} - x = 0

x^{3} + 7 x^{2} = 4 (x + 7)

x^{4} - 5 x^{3} + 9 x^{2} - 7 x + 2 = 0

What are the solutions to the equation p^3-4p=0 ?
The solutions to the equation p^3-4p=0 are p=0,p=-2,p=2
Find the zeros of p^3-4p=0
The zeros of p^3-4p=0 are p=0,p=-2,p=2