What are the solutions to the equation 2x^4-7x^2+5=0 ?

The solutions to the equation 2x^4-7x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2),x=1,x=-1

Find the zeros of 2x^4-7x^2+5=0

The zeros of 2x^4-7x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2),x=1,x=-1

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2 x^{4} - 7 x^{2} + 5 = 0

x = \frac{5}{2}, x = - \frac{5}{2}, x = 1, x = - 1

Decimal Notation

x = 1.58113 \dots, x = - 1.58113 \dots, x = 1, x = - 1

Solution steps

2 x^{4} - 7 x^{2} + 5 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

2 u^{2} - 7 u + 5 = 0

Solve

2 u^{2} - 7 u + 5 = 0 : u = \frac{5}{2}, u = 1

u = \frac{5}{2}, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = \frac{5}{2} : x = \frac{5}{2}, x = - \frac{5}{2}

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = \frac{5}{2}, x = - \frac{5}{2}, x = 1, x = - 1

5 x^{4} - 8 x^{3} = 0

x^{3} + x^{2} - 3 = 0

z^{3} = 2 i

x^{3} - 60 = x

4 x^{3} - 10 x = 0

What are the solutions to the equation 2x^4-7x^2+5=0 ?
The solutions to the equation 2x^4-7x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2),x=1,x=-1
Find the zeros of 2x^4-7x^2+5=0
The zeros of 2x^4-7x^2+5=0 are x=sqrt(5/2),x=-sqrt(5/2),x=1,x=-1