What are the solutions to the equation x^3-49x+120=0 ?

The solutions to the equation x^3-49x+120=0 are x=3,x=5,x=-8

Find the zeros of x^3-49x+120=0

The zeros of x^3-49x+120=0 are x=3,x=5,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{3} - 49 x + 120 = 0

x = 3, x = 5, x = - 8

Solution steps

x^{3} - 49 x + 120 = 0

Factor

x^{3} - 49 x + 120 : (x - 3) (x - 5) (x + 8)

(x - 3) (x - 5) (x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x - 5 = 0 or x + 8 = 0

Solve

x - 3 = 0 : x = 3

Solve

x - 5 = 0 : x = 5

Solve

x + 8 = 0 : x = - 8

The solutions are

x = 3, x = 5, x = - 8

- x^{3} + 12 x^{2} - 21 x + 10 = 0

27 x^{3} - 512 = 0

y^{3} + y^{2} = 81 y + 81

18 q - 21 q^{2} + 6 q^{3} = 0

1 + x^{4} = 0

What are the solutions to the equation x^3-49x+120=0 ?
The solutions to the equation x^3-49x+120=0 are x=3,x=5,x=-8
Find the zeros of x^3-49x+120=0
The zeros of x^3-49x+120=0 are x=3,x=5,x=-8