What are the solutions to the equation 16x=2x^4 ?

The solutions to the equation 16x=2x^4 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of 16x=2x^4

The zeros of 16x=2x^4 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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16 x = 2 x^{4}

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

16 x = 2 x^{4}

Move

2 x^{4}

to the left side

16 x - 2 x^{4} = 0

Factor

16 x - 2 x^{4} : - 2 x (x - 2) (x^{2} + 2 x + 4)

- 2 x (x - 2) (x^{2} + 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x^{2} + 2 x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 4 = 0 : x = - 1 + 3 i, x = - 1 - 3 i

The solutions are

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

- 3 x (2 x - 5) (x^{2} + 25) = 0

3 x^{2} = x^{4}

x^{6} - 7 x^{3} = 8

t^{4} = 3

2 x^{3} - 18 x = 0

What are the solutions to the equation 16x=2x^4 ?
The solutions to the equation 16x=2x^4 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of 16x=2x^4
The zeros of 16x=2x^4 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i