What are the solutions to the equation -x^3+5x^2+25x-125=0 ?

The solutions to the equation -x^3+5x^2+25x-125=0 are x=5,x=-5

Find the zeros of -x^3+5x^2+25x-125=0

The zeros of -x^3+5x^2+25x-125=0 are x=5,x=-5

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- x^{3} + 5 x^{2} + 25 x - 125 = 0

x = 5, x = - 5

Solution steps

- x^{3} + 5 x^{2} + 25 x - 125 = 0

Factor

- x^{3} + 5 x^{2} + 25 x - 125 : - (x - 5)^{2} (x + 5)

- (x - 5)^{2} (x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 5 = 0 or x + 5 = 0

Solve

x - 5 = 0 : x = 5

Solve

x + 5 = 0 : x = - 5

The solutions are

x = 5, x = - 5

z^{3} = - 1 - i

x^{2} (x + 3) = 0

y, (y - x)^{3} = C x

x^{3} + 3 x^{2} - 36 x - 108 = 0

17 + x^{3} = x^{2} + 17

What are the solutions to the equation -x^3+5x^2+25x-125=0 ?
The solutions to the equation -x^3+5x^2+25x-125=0 are x=5,x=-5
Find the zeros of -x^3+5x^2+25x-125=0
The zeros of -x^3+5x^2+25x-125=0 are x=5,x=-5