What are the solutions to the equation m^3+3m^2-4m-12=0 ?

The solutions to the equation m^3+3m^2-4m-12=0 are m=-3,m=-2,m=2

Find the zeros of m^3+3m^2-4m-12=0

The zeros of m^3+3m^2-4m-12=0 are m=-3,m=-2,m=2

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m^{3} + 3 m^{2} - 4 m - 12 = 0

m = - 3, m = - 2, m = 2

Solution steps

m^{3} + 3 m^{2} - 4 m - 12 = 0

Factor

m^{3} + 3 m^{2} - 4 m - 12 : (m + 3) (m + 2) (m - 2)

(m + 3) (m + 2) (m - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

m + 3 = 0 or m + 2 = 0 or m - 2 = 0

Solve

m + 3 = 0 : m = - 3

Solve

m + 2 = 0 : m = - 2

Solve

m - 2 = 0 : m = 2

The solutions are

m = - 3, m = - 2, m = 2

16 x^{3} - 48 x^{2} - 25 x + 75 = 0

42 x^{5} - 210 x^{4} = 0

x^{2} (1 - x) = 0

0 = x^{3} + 2 x - 1

2 x^{3} - 3 x^{2} + x = 0

What are the solutions to the equation m^3+3m^2-4m-12=0 ?
The solutions to the equation m^3+3m^2-4m-12=0 are m=-3,m=-2,m=2
Find the zeros of m^3+3m^2-4m-12=0
The zeros of m^3+3m^2-4m-12=0 are m=-3,m=-2,m=2