What are the solutions to the equation 4x^3+3x^2-60x-45=0 ?

The solutions to the equation 4x^3+3x^2-60x-45=0 are x=-3/4 ,x=-sqrt(15),x=sqrt(15)

Find the zeros of 4x^3+3x^2-60x-45=0

The zeros of 4x^3+3x^2-60x-45=0 are x=-3/4 ,x=-sqrt(15),x=sqrt(15)

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4 x^{3} + 3 x^{2} - 60 x - 45 = 0

x = - \frac{3}{4}, x = - 15, x = 15

Decimal Notation

x = - 0.75, x = - 3.87298 \dots, x = 3.87298 \dots

Solution steps

4 x^{3} + 3 x^{2} - 60 x - 45 = 0

Factor

4 x^{3} + 3 x^{2} - 60 x - 45 : (4 x + 3) (x + 15) (x - 15)

(4 x + 3) (x + 15) (x - 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 3 = 0 or x + 15 = 0 or x - 15 = 0

Solve

4 x + 3 = 0 : x = - \frac{3}{4}

Solve

x + 15 = 0 : x = - 15

Solve

x - 15 = 0 : x = 15

The solutions are

x = - \frac{3}{4}, x = - 15, x = 15

12 x^{4} - 9 x^{2} - 3 = 0

5 = c^{3}

x^{3} - 9 x + 10 = 0

x^{5} - 2 x^{4} + 1 = 0

2 x^{3} = - 128

What are the solutions to the equation 4x^3+3x^2-60x-45=0 ?
The solutions to the equation 4x^3+3x^2-60x-45=0 are x=-3/4 ,x=-sqrt(15),x=sqrt(15)
Find the zeros of 4x^3+3x^2-60x-45=0
The zeros of 4x^3+3x^2-60x-45=0 are x=-3/4 ,x=-sqrt(15),x=sqrt(15)