What are the solutions to the equation -2(9x^2-49)(x^2-5)=0 ?

The solutions to the equation -2(9x^2-49)(x^2-5)=0 are x=-7/3 ,x= 7/3 ,x=-sqrt(5),x=sqrt(5)

Find the zeros of -2(9x^2-49)(x^2-5)=0

The zeros of -2(9x^2-49)(x^2-5)=0 are x=-7/3 ,x= 7/3 ,x=-sqrt(5),x=sqrt(5)

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- 2 (9 x^{2} - 49) (x^{2} - 5) = 0

x = - \frac{7}{3}, x = \frac{7}{3}, x = - 5, x = 5

Decimal Notation

x = - 2.33333 \dots, x = 2.33333 \dots, x = - 2.23606 \dots, x = 2.23606 \dots

Solution steps

- 2 (9 x^{2} - 49) (x^{2} - 5) = 0

Factor

- 2 (9 x^{2} - 49) (x^{2} - 5) : - 2 (3 x + 7) (3 x - 7) (x + 5) (x - 5)

- 2 (3 x + 7) (3 x - 7) (x + 5) (x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 7 = 0 or 3 x - 7 = 0 or x + 5 = 0 or x - 5 = 0

Solve

3 x + 7 = 0 : x = - \frac{7}{3}

Solve

3 x - 7 = 0 : x = \frac{7}{3}

Solve

x + 5 = 0 : x = - 5

Solve

x - 5 = 0 : x = 5

The solutions are

x = - \frac{7}{3}, x = \frac{7}{3}, x = - 5, x = 5

x^{4} - 7 x^{3} + 12 x^{2} + 4 x - 16 = 0

x^{4} - 38 x^{2} + 72 = 0

- 9 x^{4} - 46 x^{2} + 5 = 0

2 x^{3} + 1 = x^{2} + 2 x

x^{633} = 9

What are the solutions to the equation -2(9x^2-49)(x^2-5)=0 ?
The solutions to the equation -2(9x^2-49)(x^2-5)=0 are x=-7/3 ,x= 7/3 ,x=-sqrt(5),x=sqrt(5)
Find the zeros of -2(9x^2-49)(x^2-5)=0
The zeros of -2(9x^2-49)(x^2-5)=0 are x=-7/3 ,x= 7/3 ,x=-sqrt(5),x=sqrt(5)