What are the solutions to the equation (81x^2-100)(x^2-14)=0 ?

The solutions to the equation (81x^2-100)(x^2-14)=0 are x=-10/9 ,x= 10/9 ,x=-sqrt(14),x=sqrt(14)

Find the zeros of (81x^2-100)(x^2-14)=0

The zeros of (81x^2-100)(x^2-14)=0 are x=-10/9 ,x= 10/9 ,x=-sqrt(14),x=sqrt(14)

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(81 x^{2} - 100) (x^{2} - 14) = 0

x = - \frac{10}{9}, x = \frac{10}{9}, x = - 14, x = 14

Decimal Notation

x = - 1.11111 \dots, x = 1.11111 \dots, x = - 3.74165 \dots, x = 3.74165 \dots

Solution steps

(81 x^{2} - 100) (x^{2} - 14) = 0

Factor

(81 x^{2} - 100) (x^{2} - 14) : (9 x + 10) (9 x - 10) (x + 14) (x - 14)

(9 x + 10) (9 x - 10) (x + 14) (x - 14) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

9 x + 10 = 0 or 9 x - 10 = 0 or x + 14 = 0 or x - 14 = 0

Solve

9 x + 10 = 0 : x = - \frac{10}{9}

Solve

9 x - 10 = 0 : x = \frac{10}{9}

Solve

x + 14 = 0 : x = - 14

Solve

x - 14 = 0 : x = 14

The solutions are

x = - \frac{10}{9}, x = \frac{10}{9}, x = - 14, x = 14

6 x + 21 x^{2} + 12 x^{3} = 0

2 x^{5} - 4 x - 7 = 0

2 x^{3} - x^{2} + 11 x - 5 = 0

12 (k (k^{2} - 4 k + 1) + 6) = 0

x^{3} - 5 x^{2} + 14 x = 0

What are the solutions to the equation (81x^2-100)(x^2-14)=0 ?
The solutions to the equation (81x^2-100)(x^2-14)=0 are x=-10/9 ,x= 10/9 ,x=-sqrt(14),x=sqrt(14)
Find the zeros of (81x^2-100)(x^2-14)=0
The zeros of (81x^2-100)(x^2-14)=0 are x=-10/9 ,x= 10/9 ,x=-sqrt(14),x=sqrt(14)