What are the solutions to the equation 4x^3=x ?

The solutions to the equation 4x^3=x are x=0,x=-1/2 ,x= 1/2

Find the zeros of 4x^3=x

The zeros of 4x^3=x are x=0,x=-1/2 ,x= 1/2

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4 x^{3} = x

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

Decimal Notation

x = 0, x = - 0.5, x = 0.5

Solution steps

4 x^{3} = x

Move

x

to the left side

4 x^{3} - x = 0

Factor

4 x^{3} - x : x (2 x + 1) (2 x - 1)

x (2 x + 1) (2 x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 2 x + 1 = 0 or 2 x - 1 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

2 x - 1 = 0 : x = \frac{1}{2}

The solutions are

x = 0, x = - \frac{1}{2}, x = \frac{1}{2}

x, 2 y^{2} = x^{3}

x^{3} + 4 x^{2} - 11 x - 30 = 0

z^{4} = 3

z^{4} = 2

x^{4} - 4 x^{3} + 4 x^{2} + 4 x - 5 = 0

What are the solutions to the equation 4x^3=x ?
The solutions to the equation 4x^3=x are x=0,x=-1/2 ,x= 1/2
Find the zeros of 4x^3=x
The zeros of 4x^3=x are x=0,x=-1/2 ,x= 1/2