What are the solutions to the equation x^4+4x^3+3x^2-4x-4=0 ?

The solutions to the equation x^4+4x^3+3x^2-4x-4=0 are x=-1,x=1,x=-2

Find the zeros of x^4+4x^3+3x^2-4x-4=0

The zeros of x^4+4x^3+3x^2-4x-4=0 are x=-1,x=1,x=-2

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x^{4} + 4 x^{3} + 3 x^{2} - 4 x - 4 = 0

x = - 1, x = 1, x = - 2

Solution steps

x^{4} + 4 x^{3} + 3 x^{2} - 4 x - 4 = 0

Factor

x^{4} + 4 x^{3} + 3 x^{2} - 4 x - 4 : (x + 1) (x - 1) (x + 2)^{2}

(x + 1) (x - 1) (x + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 1 = 0 or x + 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = - 1, x = 1, x = - 2

x^{6} + 2 x^{3} + 1 = 0

2 x^{4} - 26 x^{2} + 72 = 0

48 x - 10 x^{2} - 2 x^{3} = 0

x^{3} + 9 x^{2} - 108 = 0

2 x^{4} - x^{2} + 4 = 0

What are the solutions to the equation x^4+4x^3+3x^2-4x-4=0 ?
The solutions to the equation x^4+4x^3+3x^2-4x-4=0 are x=-1,x=1,x=-2
Find the zeros of x^4+4x^3+3x^2-4x-4=0
The zeros of x^4+4x^3+3x^2-4x-4=0 are x=-1,x=1,x=-2