What are the solutions to the equation (x-3)(x^2-4x+4)=0 ?

The solutions to the equation (x-3)(x^2-4x+4)=0 are x=3,x=2

Find the zeros of (x-3)(x^2-4x+4)=0

The zeros of (x-3)(x^2-4x+4)=0 are x=3,x=2

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(x - 3) (x^{2} - 4 x + 4) = 0

x = 3, x = 2

Solution steps

(x - 3) (x^{2} - 4 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 3 = 0 or x^{2} - 4 x + 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

x^{2} - 4 x + 4 = 0 : x = 2

The solutions are

x = 3, x = 2

x^{3} + 5 x - 7 = 0

x^{3} - 6 x^{2} + 8 x = x^{2} - 4 x

2 t^{3} + t^{2} - 10 t = 0

x^{2} (x + 1) + 4 (x + 1) = 0

2 x^{3} + 46 = 100

What are the solutions to the equation (x-3)(x^2-4x+4)=0 ?
The solutions to the equation (x-3)(x^2-4x+4)=0 are x=3,x=2
Find the zeros of (x-3)(x^2-4x+4)=0
The zeros of (x-3)(x^2-4x+4)=0 are x=3,x=2