What are the solutions to the equation 4x^3-3x-1=0 ?

The solutions to the equation 4x^3-3x-1=0 are x=1,x=-1/2

Find the zeros of 4x^3-3x-1=0

The zeros of 4x^3-3x-1=0 are x=1,x=-1/2

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4 x^{3} - 3 x - 1 = 0

x = 1, x = - \frac{1}{2}

Decimal Notation

x = 1, x = - 0.5

Solution steps

4 x^{3} - 3 x - 1 = 0

Factor

4 x^{3} - 3 x - 1 : (x - 1) (2 x + 1)^{2}

(x - 1) (2 x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions are

x = 1, x = - \frac{1}{2}

3 y^{2} + 12 y^{4} = (3 y^{2})

x^{4} - 21 x^{2} - 100 = 0

3 x (x - 1) (x - 2) = 0

0 = x^{3} - 9 x

6 x^{3} - 31 x^{2} + 3 x + 10 = 0

What are the solutions to the equation 4x^3-3x-1=0 ?
The solutions to the equation 4x^3-3x-1=0 are x=1,x=-1/2
Find the zeros of 4x^3-3x-1=0
The zeros of 4x^3-3x-1=0 are x=1,x=-1/2