What are the solutions to the equation 7x^3+48x^2=7x ?

The solutions to the equation 7x^3+48x^2=7x are x=0,x= 1/7 ,x=-7

Find the zeros of 7x^3+48x^2=7x

The zeros of 7x^3+48x^2=7x are x=0,x= 1/7 ,x=-7

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7 x^{3} + 48 x^{2} = 7 x

x = 0, x = \frac{1}{7}, x = - 7

Decimal Notation

x = 0, x = 0.14285 \dots, x = - 7

Solution steps

7 x^{3} + 48 x^{2} = 7 x

Move

7 x

to the left side

7 x^{3} + 48 x^{2} - 7 x = 0

Factor

7 x^{3} + 48 x^{2} - 7 x : x (7 x - 1) (x + 7)

x (7 x - 1) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 7 x - 1 = 0 or x + 7 = 0

Solve

7 x - 1 = 0 : x = \frac{1}{7}

Solve

x + 7 = 0 : x = - 7

The solutions are

x = 0, x = \frac{1}{7}, x = - 7

x^{4} + x^{3} - 11 x^{2} - 9 x + 18 = 0

3 x^{3} - 5 x^{2} - 2 x = 0

x^{4} + 3 x^{3} + 2 x^{2} = 0

2 x^{3} - 1 = 0

y^{4} + 16 y^{2} - 225 = 0

What are the solutions to the equation 7x^3+48x^2=7x ?
The solutions to the equation 7x^3+48x^2=7x are x=0,x= 1/7 ,x=-7
Find the zeros of 7x^3+48x^2=7x
The zeros of 7x^3+48x^2=7x are x=0,x= 1/7 ,x=-7