What are the solutions to the equation (1+x)^9=2 ?

The solutions to the equation (1+x)^9=2 are x=\sqrt[9]{2}-1

Find the zeros of (1+x)^9=2

The zeros of (1+x)^9=2 are x=\sqrt[9]{2}-1

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(1 + x)^{9} = 2

Decimal Notation

x = 0.08005 \dots

Solution steps

(1 + x)^{9} = 2

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

a^{3} = 3

y, x + y^{3} = 27

x^{3} - 9 x^{2} + 15 x + 25 = 0

x^{3} - 9 x - 3 = 0

(x^{2} + 3)^{2} + 7 x^{2} + 21 = - 10

What are the solutions to the equation (1+x)^9=2 ?
The solutions to the equation (1+x)^9=2 are x=\sqrt[9]{2}-1
Find the zeros of (1+x)^9=2
The zeros of (1+x)^9=2 are x=\sqrt[9]{2}-1