What are the solutions to the equation 5y(y-4)(y-7)=0 ?

The solutions to the equation 5y(y-4)(y-7)=0 are y=0,y=4,y=7

Find the zeros of 5y(y-4)(y-7)=0

The zeros of 5y(y-4)(y-7)=0 are y=0,y=4,y=7

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5 y (y - 4) (y - 7) = 0

y = 0, y = 4, y = 7

Solution steps

5 y (y - 4) (y - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or y - 4 = 0 or y - 7 = 0

Solve

y - 4 = 0 : y = 4

Solve

y - 7 = 0 : y = 7

The solutions are

y = 0, y = 4, y = 7

8 - x^{3} = 0

x^{7} - 28 x^{4} + 27 x = 0

x^{3} = 5 x^{2}

2 x (4 x^{2} - 4 x + 1) = x (8 x) + 4 (2 x)

18 x^{3} - 27 x^{2} - 50 x + 75 = 0

What are the solutions to the equation 5y(y-4)(y-7)=0 ?
The solutions to the equation 5y(y-4)(y-7)=0 are y=0,y=4,y=7
Find the zeros of 5y(y-4)(y-7)=0
The zeros of 5y(y-4)(y-7)=0 are y=0,y=4,y=7