What are the solutions to the equation 2x(x-2)(36x^2-25)=0 ?

The solutions to the equation 2x(x-2)(36x^2-25)=0 are x=0,x=2,x=-5/6 ,x= 5/6

Find the zeros of 2x(x-2)(36x^2-25)=0

The zeros of 2x(x-2)(36x^2-25)=0 are x=0,x=2,x=-5/6 ,x= 5/6

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2 x (x - 2) (36 x^{2} - 25) = 0

x = 0, x = 2, x = - \frac{5}{6}, x = \frac{5}{6}

Decimal Notation

x = 0, x = 2, x = - 0.83333 \dots, x = 0.83333 \dots

Solution steps

2 x (x - 2) (36 x^{2} - 25) = 0

Factor

2 x (x - 2) (36 x^{2} - 25) : 2 x (x - 2) (6 x + 5) (6 x - 5)

2 x (x - 2) (6 x + 5) (6 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or 6 x + 5 = 0 or 6 x - 5 = 0

Solve

x - 2 = 0 : x = 2

Solve

6 x + 5 = 0 : x = - \frac{5}{6}

Solve

6 x - 5 = 0 : x = \frac{5}{6}

The solutions are

x = 0, x = 2, x = - \frac{5}{6}, x = \frac{5}{6}

2 x^{3} - 32 x = 0

x^{3} - x^{2} + 5 = 0

- 6 = b^{18}

0.5 x^{3} - 6.5 x^{2} + 15 x = 0

x^{3} - 3 x^{2} - 2 = 0

What are the solutions to the equation 2x(x-2)(36x^2-25)=0 ?
The solutions to the equation 2x(x-2)(36x^2-25)=0 are x=0,x=2,x=-5/6 ,x= 5/6
Find the zeros of 2x(x-2)(36x^2-25)=0
The zeros of 2x(x-2)(36x^2-25)=0 are x=0,x=2,x=-5/6 ,x= 5/6