What are the solutions to the equation -x^3+3x^2-7x+5=0 ?

The solutions to the equation -x^3+3x^2-7x+5=0 are x=1,x=1+2i,x=1-2i

Find the zeros of -x^3+3x^2-7x+5=0

The zeros of -x^3+3x^2-7x+5=0 are x=1,x=1+2i,x=1-2i

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- x^{3} + 3 x^{2} - 7 x + 5 = 0

x = 1, x = 1 + 2 i, x = 1 - 2 i

Solution steps

- x^{3} + 3 x^{2} - 7 x + 5 = 0

Factor

- x^{3} + 3 x^{2} - 7 x + 5 : - (x - 1) (x^{2} - 2 x + 5)

- (x - 1) (x^{2} - 2 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x^{2} - 2 x + 5 = 0

Solve

x - 1 = 0 : x = 1

Solve

x^{2} - 2 x + 5 = 0 : x = 1 + 2 i, x = 1 - 2 i

The solutions are

x = 1, x = 1 + 2 i, x = 1 - 2 i

8 x^{4} (x - 1) = 7

3 x^{2} - 2 x^{4} + 7 = 0

0.037 = (1 + \frac{x}{12})^{12} - 1

14 x^{4} - 5 x^{2} - 1 = 0

x^{3} - 2 x^{2} - 5 x + 1 = 0

What are the solutions to the equation -x^3+3x^2-7x+5=0 ?
The solutions to the equation -x^3+3x^2-7x+5=0 are x=1,x=1+2i,x=1-2i
Find the zeros of -x^3+3x^2-7x+5=0
The zeros of -x^3+3x^2-7x+5=0 are x=1,x=1+2i,x=1-2i