What are the solutions to the equation x(x^3-8)=0 ?

The solutions to the equation x(x^3-8)=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

Find the zeros of x(x^3-8)=0

The zeros of x(x^3-8)=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i

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x (x^{3} - 8) = 0

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

Solution steps

x (x^{3} - 8) = 0

Factor

x (x^{3} - 8) : x (x - 2) (x^{2} + 2 x + 4)

x (x - 2) (x^{2} + 2 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0 or x^{2} + 2 x + 4 = 0

Solve

x - 2 = 0 : x = 2

Solve

x^{2} + 2 x + 4 = 0 : x = - 1 + 3 i, x = - 1 - 3 i

The solutions are

x = 0, x = 2, x = - 1 + 3 i, x = - 1 - 3 i

r, x = \frac{5}{3} π r^{3}

4 x^{3} - 6 x^{2} - 3 = \frac{1}{2}

x^{4} - 4 x^{2} - 45 = 0

x^{4} - 4 x^{2} = - 3

x^{3} - 14 x^{2} + 59 x - 70 = 0

What are the solutions to the equation x(x^3-8)=0 ?
The solutions to the equation x(x^3-8)=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i
Find the zeros of x(x^3-8)=0
The zeros of x(x^3-8)=0 are x=0,x=2,x=-1+sqrt(3)i,x=-1-sqrt(3)i