What are the solutions to the equation solvefor x,12x^5=(4x^2)(C) ?

The solutions to the equation solvefor x,12x^5=(4x^2)(C) are

Find the zeros of solvefor x,12x^5=(4x^2)(C)

The zeros of solvefor x,12x^5=(4x^2)(C) are

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solve for

x, 12 x^{5} = (4 x^{2}) (C)

Solution steps

12 x^{5} = (4 x^{2}) (C)

Move

(4 x^{2}) (C)

to the left side

12 x^{5} - 4 x^{2} C = 0

Factor

12 x^{5} - 4 x^{2} C : 4 x^{2} (3 x^{3} - C)

4 x^{2} (3 x^{3} - C) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x^{3} - C = 0

Solve

The solutions are

x^{3} + 8 x^{2} - 29 x + 44 = 0

x^{3} - 3 x^{2} + 6 = 0

y, y^{4} = x^{3} - 16 x

x^{6} - 2 x^{3} + 1 = 0

(x^{2} - 4) (x^{2} + 1) (x - 3) = 0

What are the solutions to the equation solvefor x,12x^5=(4x^2)(C) ?
The solutions to the equation solvefor x,12x^5=(4x^2)(C) are
Find the zeros of solvefor x,12x^5=(4x^2)(C)
The zeros of solvefor x,12x^5=(4x^2)(C) are