What are the solutions to the equation x(x^2-36)(9x^2-4)=0 ?

The solutions to the equation x(x^2-36)(9x^2-4)=0 are x=0,x=-6,x=6,x=-2/3 ,x= 2/3

Find the zeros of x(x^2-36)(9x^2-4)=0

The zeros of x(x^2-36)(9x^2-4)=0 are x=0,x=-6,x=6,x=-2/3 ,x= 2/3

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x (x^{2} - 36) (9 x^{2} - 4) = 0

x = 0, x = - 6, x = 6, x = - \frac{2}{3}, x = \frac{2}{3}

Decimal Notation

x = 0, x = - 6, x = 6, x = - 0.66666 \dots, x = 0.66666 \dots

Solution steps

x (x^{2} - 36) (9 x^{2} - 4) = 0

Factor

x (x^{2} - 36) (9 x^{2} - 4) : x (x + 6) (x - 6) (3 x + 2) (3 x - 2)

x (x + 6) (x - 6) (3 x + 2) (3 x - 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 6 = 0 or x - 6 = 0 or 3 x + 2 = 0 or 3 x - 2 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

The solutions are

x = 0, x = - 6, x = 6, x = - \frac{2}{3}, x = \frac{2}{3}

- 25 x^{4} + 9 x^{2} = 0

4 x^{3} - 2 x^{2} - 4 x - 1 = 0

6 x - x^{2} - x^{3} = 0

5 (3 k + 2) = k^{2} (k - 7)

27 x^{6} + 26 x^{3} - 1 = 0

What are the solutions to the equation x(x^2-36)(9x^2-4)=0 ?
The solutions to the equation x(x^2-36)(9x^2-4)=0 are x=0,x=-6,x=6,x=-2/3 ,x= 2/3
Find the zeros of x(x^2-36)(9x^2-4)=0
The zeros of x(x^2-36)(9x^2-4)=0 are x=0,x=-6,x=6,x=-2/3 ,x= 2/3