What are the solutions to the equation x^4-12x^2=0 ?

The solutions to the equation x^4-12x^2=0 are x=2sqrt(3),x=-2sqrt(3),x=0

Find the zeros of x^4-12x^2=0

The zeros of x^4-12x^2=0 are x=2sqrt(3),x=-2sqrt(3),x=0

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x^{4} - 12 x^{2} = 0

x = 23, x = - 23, x = 0

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots, x = 0

Solution steps

x^{4} - 12 x^{2} = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 12 u = 0

Solve

u^{2} - 12 u = 0 : u = 12, u = 0

u = 12, u = 0

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 12 : x = 23, x = - 23

Solve

x^{2} = 0 : x = 0

The solutions are

x = 23, x = - 23, x = 0

x^{6} - 14 x^{3} + 40 = 0

x, x^{3} + y^{3} = 9

x, x^{3} + y^{3} = 6

3 x^{5} - 5 x^{3} = 0

60 x^{5} + 120 x^{4} + 60 x^{3} = 0

What are the solutions to the equation x^4-12x^2=0 ?
The solutions to the equation x^4-12x^2=0 are x=2sqrt(3),x=-2sqrt(3),x=0
Find the zeros of x^4-12x^2=0
The zeros of x^4-12x^2=0 are x=2sqrt(3),x=-2sqrt(3),x=0