What are the solutions to the equation 4x(x+1)(x-1)=0 ?

The solutions to the equation 4x(x+1)(x-1)=0 are x=0,x=-1,x=1

Find the zeros of 4x(x+1)(x-1)=0

The zeros of 4x(x+1)(x-1)=0 are x=0,x=-1,x=1

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4 x (x + 1) (x - 1) = 0

x = 0, x = - 1, x = 1

Solution steps

4 x (x + 1) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x - 1 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 1 = 0 : x = 1

The solutions are

x = 0, x = - 1, x = 1

0 = 3 x^{4} - 8 x^{3} + 6 x^{2}

(z + 1)^{4} + 16 = 0

x^{3} + 4 x^{2} + 8 x = 0

3 = 0.03 x^{3} + 0.05 x^{2}

- 12 x^{5} - 6 x^{3} + 10 = 0

What are the solutions to the equation 4x(x+1)(x-1)=0 ?
The solutions to the equation 4x(x+1)(x-1)=0 are x=0,x=-1,x=1
Find the zeros of 4x(x+1)(x-1)=0
The zeros of 4x(x+1)(x-1)=0 are x=0,x=-1,x=1