What are the solutions to the equation 2x^3-5x^2+50x-125=0 ?

The solutions to the equation 2x^3-5x^2+50x-125=0 are x= 5/2 ,x=5i,x=-5i

Find the zeros of 2x^3-5x^2+50x-125=0

The zeros of 2x^3-5x^2+50x-125=0 are x= 5/2 ,x=5i,x=-5i

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2 x^{3} - 5 x^{2} + 50 x - 125 = 0

x = \frac{5}{2}, x = 5 i, x = - 5 i

Solution steps

2 x^{3} - 5 x^{2} + 50 x - 125 = 0

Factor

2 x^{3} - 5 x^{2} + 50 x - 125 : (2 x - 5) (x^{2} + 25)

(2 x - 5) (x^{2} + 25) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or x^{2} + 25 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

x^{2} + 25 = 0 : x = 5 i, x = - 5 i

The solutions are

x = \frac{5}{2}, x = 5 i, x = - 5 i

- 14 x^{3} + 21 x^{2} - 3 = 0

x^{5} = 5 x - 4 x^{3}

2 x (7 x + 1) (9 x^{2} - 25) = 0

6 x^{4} - 14 x^{2} = 0

3 x^{6} + 4 x^{4} + 4 x^{2} + 1 = 0

What are the solutions to the equation 2x^3-5x^2+50x-125=0 ?
The solutions to the equation 2x^3-5x^2+50x-125=0 are x= 5/2 ,x=5i,x=-5i
Find the zeros of 2x^3-5x^2+50x-125=0
The zeros of 2x^3-5x^2+50x-125=0 are x= 5/2 ,x=5i,x=-5i