What are the solutions to the equation -λ^3+12λ+16=0 ?

The solutions to the equation -λ^3+12λ+16=0 are λ=-2,λ=4

Find the zeros of -λ^3+12λ+16=0

The zeros of -λ^3+12λ+16=0 are λ=-2,λ=4

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- λ^{3} + 12 λ + 16 = 0

λ = - 2, λ = 4

Solution steps

- λ^{3} + 12 λ + 16 = 0

Factor

- λ^{3} + 12 λ + 16 : - (λ + 2)^{2} (λ - 4)

- (λ + 2)^{2} (λ - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

λ + 2 = 0 or λ - 4 = 0

Solve

λ + 2 = 0 : λ = - 2

Solve

λ - 4 = 0 : λ = 4

The solutions are

λ = - 2, λ = 4

k^{3} = 729

0 = - 25 x^{4} + 9 x^{2}

x^{3} - 3 x^{2} - 10 x + 30 = 0

x, y^{2} + 24 = x^{3}

(x - 2)^{3} + 3 (x - 2)^{2} = 0

What are the solutions to the equation -λ^3+12λ+16=0 ?
The solutions to the equation -λ^3+12λ+16=0 are λ=-2,λ=4
Find the zeros of -λ^3+12λ+16=0
The zeros of -λ^3+12λ+16=0 are λ=-2,λ=4