What are the solutions to the equation 0=x^3+x^2-12x ?

The solutions to the equation 0=x^3+x^2-12x are x=0,x=3,x=-4

Find the zeros of 0=x^3+x^2-12x

The zeros of 0=x^3+x^2-12x are x=0,x=3,x=-4

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0 = x^{3} + x^{2} - 12 x

x = 0, x = 3, x = - 4

Solution steps

0 = x^{3} + x^{2} - 12 x

Switch sides

x^{3} + x^{2} - 12 x = 0

Factor

x^{3} + x^{2} - 12 x : x (x - 3) (x + 4)

x (x - 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 3 = 0 or x + 4 = 0

Solve

x - 3 = 0 : x = 3

Solve

x + 4 = 0 : x = - 4

The solutions are

x = 0, x = 3, x = - 4

5 x^{4} = 0

x^{3} - 11 x^{2} + 24 x = 0

R^{4} + R^{2} - 2 = 0

25 = x^{4}

(x + 3)^{3} = 0

What are the solutions to the equation 0=x^3+x^2-12x ?
The solutions to the equation 0=x^3+x^2-12x are x=0,x=3,x=-4
Find the zeros of 0=x^3+x^2-12x
The zeros of 0=x^3+x^2-12x are x=0,x=3,x=-4