What are the solutions to the equation p^2+8p+16=0 ?

The solutions to the equation p^2+8p+16=0 are p=-4

Find the zeros of p^2+8p+16=0

The zeros of p^2+8p+16=0 are p=-4

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p^{2} + 8 p + 16 = 0

p = - 4

Solution steps

p^{2} + 8 p + 16 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 16}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 16 = 0

p_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 1}

p = \frac{- 8}{2 \cdot 1}

\frac{- 8}{2 \cdot 1} = - 4

p = - 4

The solution to the quadratic equation is:

p = - 4

z, - p (d + z) = 2 z + 59

\frac{7 !}{4 ! ( 7 - 4 ) !}

27 p^{3} - 8 c^{3}

6 \leq x

(- 8) \frac{4}{3}

What are the solutions to the equation p^2+8p+16=0 ?
The solutions to the equation p^2+8p+16=0 are p=-4
Find the zeros of p^2+8p+16=0
The zeros of p^2+8p+16=0 are p=-4