What are the solutions to the equation -x^3-6x^2-12x-8=0 ?

The solutions to the equation -x^3-6x^2-12x-8=0 are x=-2

Find the zeros of -x^3-6x^2-12x-8=0

The zeros of -x^3-6x^2-12x-8=0 are x=-2

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- x^{3} - 6 x^{2} - 12 x - 8 = 0

x = - 2

Solution steps

- x^{3} - 6 x^{2} - 12 x - 8 = 0

Factor

- x^{3} - 6 x^{2} - 12 x - 8 : - (x + 2)^{3}

- (x + 2)^{3} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0

Solve

x + 2 = 0 : x = - 2

The solution is

x = - 2

x^{3} + 5 x^{2} - 6 x = 0

2 (x + 6) (x^{2} + 36) = 0

x^{5} + 2 x - 2 = 0

- x^{3} + 5 x^{2} - 3 x = 1

x^{3} - 3 x^{2} - 6 x - 8 = 0

What are the solutions to the equation -x^3-6x^2-12x-8=0 ?
The solutions to the equation -x^3-6x^2-12x-8=0 are x=-2
Find the zeros of -x^3-6x^2-12x-8=0
The zeros of -x^3-6x^2-12x-8=0 are x=-2