What are the solutions to the equation x^3+2x^2=81x+162 ?

The solutions to the equation x^3+2x^2=81x+162 are x=-2,x=-9,x=9

Find the zeros of x^3+2x^2=81x+162

The zeros of x^3+2x^2=81x+162 are x=-2,x=-9,x=9

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x^{3} + 2 x^{2} = 81 x + 162

x = - 2, x = - 9, x = 9

Solution steps

x^{3} + 2 x^{2} = 81 x + 162

Move

162

to the left side

x^{3} + 2 x^{2} - 162 = 81 x

Move

81 x

to the left side

x^{3} + 2 x^{2} - 162 - 81 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

x^{3} + 2 x^{2} - 81 x - 162 = 0

Factor

x^{3} + 2 x^{2} - 81 x - 162 : (x + 2) (x + 9) (x - 9)

(x + 2) (x + 9) (x - 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or x + 9 = 0 or x - 9 = 0

Solve

x + 2 = 0 : x = - 2

Solve

x + 9 = 0 : x = - 9

Solve

x - 9 = 0 : x = 9

The solutions are

x = - 2, x = - 9, x = 9

6 t^{3} - 4 t^{2} = 16 t

3 x^{3} + x^{2} + 12 x + 4 = 0

m^{3} = - 1000

x^{4} - x = 1

4350 = 45000 (1 - k)^{6}

What are the solutions to the equation x^3+2x^2=81x+162 ?
The solutions to the equation x^3+2x^2=81x+162 are x=-2,x=-9,x=9
Find the zeros of x^3+2x^2=81x+162
The zeros of x^3+2x^2=81x+162 are x=-2,x=-9,x=9