What are the solutions to the equation 2x(x+1)(x^2-36)=0 ?

The solutions to the equation 2x(x+1)(x^2-36)=0 are x=0,x=-1,x=-6,x=6

Find the zeros of 2x(x+1)(x^2-36)=0

The zeros of 2x(x+1)(x^2-36)=0 are x=0,x=-1,x=-6,x=6

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2 x (x + 1) (x^{2} - 36) = 0

x = 0, x = - 1, x = - 6, x = 6

Solution steps

2 x (x + 1) (x^{2} - 36) = 0

Factor

2 x (x + 1) (x^{2} - 36) : 2 x (x + 1) (x + 6) (x - 6)

2 x (x + 1) (x + 6) (x - 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x + 1 = 0 or x + 6 = 0 or x - 6 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 6 = 0 : x = - 6

Solve

x - 6 = 0 : x = 6

The solutions are

x = 0, x = - 1, x = - 6, x = 6

x^{3} - 9 x^{2} + 20 x - 12 = 0

x^{4} - 37 x^{2} = - 36

- x^{3} + 2 x^{2} + 3 = 0

20 x^{4} - x^{2} - 1 = 0

x^{5} - 2 = 0

What are the solutions to the equation 2x(x+1)(x^2-36)=0 ?
The solutions to the equation 2x(x+1)(x^2-36)=0 are x=0,x=-1,x=-6,x=6
Find the zeros of 2x(x+1)(x^2-36)=0
The zeros of 2x(x+1)(x^2-36)=0 are x=0,x=-1,x=-6,x=6