What are the solutions to the equation x^3= 125/27 ?

The solutions to the equation x^3= 125/27 are x= 5/3 ,x=-5/6+5/(2sqrt(3))i,x=-5/6-5/(2sqrt(3))i

Find the zeros of x^3= 125/27

The zeros of x^3= 125/27 are x= 5/3 ,x=-5/6+5/(2sqrt(3))i,x=-5/6-5/(2sqrt(3))i

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x^{3} = \frac{125}{27}

x = \frac{5}{3}, x = - \frac{5}{6} + \frac{5}{2 3} i, x = - \frac{5}{6} - \frac{5}{2 3} i

Solution steps

x^{3} = \frac{125}{27}

For

x^{3} = f (a)

the solutions are

Simplify

x = \frac{5}{3}, x = - \frac{5}{6} + \frac{5}{2 3} i, x = - \frac{5}{6} - \frac{5}{2 3} i

10 = 500 b^{3}

(x^{2} - 9)^{2} - x^{2} + 10 = 1

x^{3} - 5 x^{2} - 2 x + 10 = 0

8 x^{3} - 4 x = \frac{1}{2}

x^{4} + 7 x^{3} + 6 x^{2} - 22 x + 8 = 0

What are the solutions to the equation x^3= 125/27 ?
The solutions to the equation x^3= 125/27 are x= 5/3 ,x=-5/6+5/(2sqrt(3))i,x=-5/6-5/(2sqrt(3))i
Find the zeros of x^3= 125/27
The zeros of x^3= 125/27 are x= 5/3 ,x=-5/6+5/(2sqrt(3))i,x=-5/6-5/(2sqrt(3))i