What are the solutions to the equation 2x^3+x^2-26x-13=0 ?

The solutions to the equation 2x^3+x^2-26x-13=0 are x=-1/2 ,x=-sqrt(13),x=sqrt(13)

Find the zeros of 2x^3+x^2-26x-13=0

The zeros of 2x^3+x^2-26x-13=0 are x=-1/2 ,x=-sqrt(13),x=sqrt(13)

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2 x^{3} + x^{2} - 26 x - 13 = 0

x = - \frac{1}{2}, x = - 13, x = 13

Decimal

x = - 0.5, x = - 3.60555 \dots, x = 3.60555 \dots

Solution steps

2 x^{3} + x^{2} - 26 x - 13 = 0

Factor

2 x^{3} + x^{2} - 26 x - 13 : (2 x + 1) (x + 13) (x - 13)

(2 x + 1) (x + 13) (x - 13) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 1 = 0 or x + 13 = 0 or x - 13 = 0

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

Solve

x + 13 = 0 : x = - 13

Solve

x - 13 = 0 : x = 13

The solutions are

x = - \frac{1}{2}, x = - 13, x = 13

x (x + 1)^{2} - 1 = 0

x^{4} + 8 x^{2} + 15 = 0

4 y^{3} - 2 = y - 8 y^{2}

x^{3} - x - 3 = 0

- x + x^{3} = 0

What are the solutions to the equation 2x^3+x^2-26x-13=0 ?
The solutions to the equation 2x^3+x^2-26x-13=0 are x=-1/2 ,x=-sqrt(13),x=sqrt(13)
Find the zeros of 2x^3+x^2-26x-13=0
The zeros of 2x^3+x^2-26x-13=0 are x=-1/2 ,x=-sqrt(13),x=sqrt(13)