What are the solutions to the equation x^3+3x^2+9x+27=0 ?

The solutions to the equation x^3+3x^2+9x+27=0 are x=-3,x=3i,x=-3i

Find the zeros of x^3+3x^2+9x+27=0

The zeros of x^3+3x^2+9x+27=0 are x=-3,x=3i,x=-3i

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x^{3} + 3 x^{2} + 9 x + 27 = 0

x = - 3, x = 3 i, x = - 3 i

Solution steps

x^{3} + 3 x^{2} + 9 x + 27 = 0

Factor

x^{3} + 3 x^{2} + 9 x + 27 : (x + 3) (x^{2} + 9)

(x + 3) (x^{2} + 9) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x^{2} + 9 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x^{2} + 9 = 0 : x = 3 i, x = - 3 i

The solutions are

x = - 3, x = 3 i, x = - 3 i

x (x - 2)^{2} = 0

9 x^{4} - 9 x^{2} + 2 = 0

2 x^{8} - 3 + 5 = 20

x^{2} 2 x^{1} = 0

3 v + 126 = 4 v^{3}

What are the solutions to the equation x^3+3x^2+9x+27=0 ?
The solutions to the equation x^3+3x^2+9x+27=0 are x=-3,x=3i,x=-3i
Find the zeros of x^3+3x^2+9x+27=0
The zeros of x^3+3x^2+9x+27=0 are x=-3,x=3i,x=-3i