What are the solutions to the equation 2x^3+4-6x=0 ?

The solutions to the equation 2x^3+4-6x=0 are x=1,x=-2

Find the zeros of 2x^3+4-6x=0

The zeros of 2x^3+4-6x=0 are x=1,x=-2

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2 x^{3} + 4 - 6 x = 0

x = 1, x = - 2

Solution steps

2 x^{3} + 4 - 6 x = 0

Write in the standard form

a_{n} x^{n} + \dots + a_{1} x + a_{0} = 0

2 x^{3} - 6 x + 4 = 0

Factor

2 x^{3} - 6 x + 4 : 2 (x - 1)^{2} (x + 2)

2 (x - 1)^{2} (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = - 2

- 12 + 14 (x^{2} - 3) = 2 (x^{2} - 3)^{2}

x^{3} + 6 x^{2} + 9 = 0

x^{3} - 3 x^{2} - 4 x = 0

x^{3} + x - 30 = 0

3 x^{3} - 48 x = 0

What are the solutions to the equation 2x^3+4-6x=0 ?
The solutions to the equation 2x^3+4-6x=0 are x=1,x=-2
Find the zeros of 2x^3+4-6x=0
The zeros of 2x^3+4-6x=0 are x=1,x=-2