What are the solutions to the equation x^2(x-3)=-4 ?

The solutions to the equation x^2(x-3)=-4 are x=-1,x=2

Find the zeros of x^2(x-3)=-4

The zeros of x^2(x-3)=-4 are x=-1,x=2

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x^{2} (x - 3) = - 4

x = - 1, x = 2

Solution steps

x^{2} (x - 3) = - 4

Expand

x^{2} (x - 3) : x^{3} - 3 x^{2}

x^{3} - 3 x^{2} = - 4

Move

4

to the left side

x^{3} - 3 x^{2} + 4 = 0

Factor

x^{3} - 3 x^{2} + 4 : (x + 1) (x - 2)^{2}

(x + 1) (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 2 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 2 = 0 : x = 2

The solutions are

x = - 1, x = 2

x^{3} - 9 x^{2} + 9 x - 81 = 0

x^{4} = - 2

x^{4} = 10

x^{4} = 20

x^{4} - 4 x + 3 = 0

What are the solutions to the equation x^2(x-3)=-4 ?
The solutions to the equation x^2(x-3)=-4 are x=-1,x=2
Find the zeros of x^2(x-3)=-4
The zeros of x^2(x-3)=-4 are x=-1,x=2