What are the solutions to the equation 3x^3+12x=12x^2 ?

The solutions to the equation 3x^3+12x=12x^2 are x=0,x=2

Find the zeros of 3x^3+12x=12x^2

The zeros of 3x^3+12x=12x^2 are x=0,x=2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{3} + 12 x = 12 x^{2}

x = 0, x = 2

Solution steps

3 x^{3} + 12 x = 12 x^{2}

Move

12 x^{2}

to the left side

3 x^{3} + 12 x - 12 x^{2} = 0

Factor

3 x^{3} + 12 x - 12 x^{2} : 3 x (x - 2)^{2}

3 x (x - 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 2 = 0

Solve

x - 2 = 0 : x = 2

The solutions are

x = 0, x = 2

3 x^{5} + 15 x = 18 x^{3}

x^{4} + x - 2 = 0

x^{3} + 3 x^{2} + 3 x = 7

x^{4} - 4 = 3 x^{2}

x, g (1 + h) = x^{3}

What are the solutions to the equation 3x^3+12x=12x^2 ?
The solutions to the equation 3x^3+12x=12x^2 are x=0,x=2
Find the zeros of 3x^3+12x=12x^2
The zeros of 3x^3+12x=12x^2 are x=0,x=2