What are the solutions to the equation 2x^3+5x^2-x-6=0 ?

The solutions to the equation 2x^3+5x^2-x-6=0 are x=1,x=-3/2 ,x=-2

Find the zeros of 2x^3+5x^2-x-6=0

The zeros of 2x^3+5x^2-x-6=0 are x=1,x=-3/2 ,x=-2

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2 x^{3} + 5 x^{2} - x - 6 = 0

x = 1, x = - \frac{3}{2}, x = - 2

Decimal Notation

x = 1, x = - 1.5, x = - 2

Solution steps

2 x^{3} + 5 x^{2} - x - 6 = 0

Factor

2 x^{3} + 5 x^{2} - x - 6 : (x - 1) (2 x + 3) (x + 2)

(x - 1) (2 x + 3) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 3 = 0 or x + 2 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

x + 2 = 0 : x = - 2

The solutions are

x = 1, x = - \frac{3}{2}, x = - 2

- x^{3} + 3 x^{2} + 10 x - 24 = 0

x^{4} + x^{2} + 2 = 0

x, x^{3} - 4 x^{2} + x + 6 = 0

x^{3} - 5 x^{2} - 5 x + 25 = 0

- 1 = x^{3}

What are the solutions to the equation 2x^3+5x^2-x-6=0 ?
The solutions to the equation 2x^3+5x^2-x-6=0 are x=1,x=-3/2 ,x=-2
Find the zeros of 2x^3+5x^2-x-6=0
The zeros of 2x^3+5x^2-x-6=0 are x=1,x=-3/2 ,x=-2