What are the solutions to the equation 36x^3+24x^2=-4x ?

The solutions to the equation 36x^3+24x^2=-4x are x=0,x=-1/3

Find the zeros of 36x^3+24x^2=-4x

The zeros of 36x^3+24x^2=-4x are x=0,x=-1/3

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36 x^{3} + 24 x^{2} = - 4 x

x = 0, x = - \frac{1}{3}

Decimal Notation

x = 0, x = - 0.33333 \dots

Solution steps

36 x^{3} + 24 x^{2} = - 4 x

Move

4 x

to the left side

36 x^{3} + 24 x^{2} + 4 x = 0

Factor

36 x^{3} + 24 x^{2} + 4 x : 4 x (3 x + 1)^{2}

4 x (3 x + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or 3 x + 1 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

The solutions are

x = 0, x = - \frac{1}{3}

x^{3} + 2 x^{2} - 6 x + 9 = 0

25 x^{3} - 75 x^{2} - 9 x + 27 = 0

x^{3} - x^{2} = 2 x

x, x^{3} + 8 = 0

2.08 = x^{3} + x

What are the solutions to the equation 36x^3+24x^2=-4x ?
The solutions to the equation 36x^3+24x^2=-4x are x=0,x=-1/3
Find the zeros of 36x^3+24x^2=-4x
The zeros of 36x^3+24x^2=-4x are x=0,x=-1/3